If it's not what You are looking for type in the equation solver your own equation and let us solve it.
34+4x=x^2
We move all terms to the left:
34+4x-(x^2)=0
determiningTheFunctionDomain -x^2+4x+34=0
We add all the numbers together, and all the variables
-1x^2+4x+34=0
a = -1; b = 4; c = +34;
Δ = b2-4ac
Δ = 42-4·(-1)·34
Δ = 152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{152}=\sqrt{4*38}=\sqrt{4}*\sqrt{38}=2\sqrt{38}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{38}}{2*-1}=\frac{-4-2\sqrt{38}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{38}}{2*-1}=\frac{-4+2\sqrt{38}}{-2} $
| 8x+27+3x-2+3x+1=180 | | r2-10r+10=0 | | (x-6)2=12-2x | | x+20=–5x+1 | | 4.2-3x=-3x+6.1 | | 8x+24=8(x+2) | | 8x+27+3x-2=3x+1 | | -11+2d=3 | | b/3=3.73 | | 9-5x=1-7x | | 2.7(x-6)=-5.6x+8 | | -4K+10k-12=35-39 | | 8x+24=2(2x+4) | | (2^x)-(2^-x)=4 | | x+2=(2(x-1 | | -58.109=f+0.07 | | 60=10/n | | 6(5-8v)+12=+34 | | (9x-2)+3x=118 | | p-1/4*3=-3/5 | | 236=c+183 | | 8x+24=4(2x+8) | | |3+6x|=4x+11 | | d-5.7=14.05 | | 25/3x=2x+1 | | y+105=227 | | D+4d+3=33 | | 1=1/2(6q+8)-6 | | 7(y+8)=2y+16 | | 8x+24=5(3x+2) | | 8x+30=23 | | u+84=7u |